Second Largest Number In Array Java

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Second Largest Number In Array Java

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01 Find The Second Largest Number In Array Java YouTube

Finding the second largest value in an array using java my question is that I need to find the second largest value from my array but I am getting the same value which is equal to the first value please help if nums x max max nums x if nums x secmax secmax max secmax nums x public void findMax(int a[]) { int large = Integer.MIN_VALUE; int secondLarge = Integer.MIN_VALUE; for (int i = 0; i < a.length; i++) { if (large < a[i]) { secondLarge = large; large = a[i]; } else if (a[i] > secondLarge) { if (a[i] != large) { secondLarge = a[i]; } } } System.out.println("Large number " + large + " Second Large number .

Java Program To Find Largest Array Number

Second Largest Number In Array JavaProblem: The problem is to get the second largest array element. Observation: Second largest number is defined as the number that has the minimum difference when subtracted from the maximum element in the array. Solution: This is a two pass solution. First pass is to find the maximum number. Examples Input arr 12 35 1 10 34 1 Output The second largest element is 34 Explanation The largest element of the array is 35 and the second largest element is 34 Input arr 10 5 10 Output The second largest element is 5

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